This problem has been solved. What power is needed to lift a 49 kg person a vertical distance of 5 0 m in 20 0 s.

### Work done force into distance.

**What power is needed to lift a 49 kg person**. Your force will be the mass of the person 49 kg times the force of gravity 9 8 m s 2 when you multiply those two you get 480 2 n as your f. G acceleration of gravity 9 8 m s to better understand the statement let s apply the formula of the work performed by a force. What power is needed to lift a 49 kg person a vertical distance of 5 0 m in 20 0 s.

To lift a 49 kg person you need a force of 49 kg g 49 kg 9 8 m s 2 480 2 n. Plug it into the work formula w 480 2. In watt m mass 49 kg d displacement 5 m t time 20 s adopt.

What power is needed to lift a 49 kg person a vertical distance of 5 0 m in 20 0 s. So force here would be weight. 2401 20 seconds.

49kg x 9 8 x 5 meters the work needed. So the answer should be. A warehouse worker uses a forklift to lift a crate of pickles on a platform to a height 2 75 m above the floor.

Power work time. Power work time work force distance in our case force m g lifting force is equal to weight of the body now numbers m 49kg distance 5m time 20s g 10h kg force m g 49kg 10n kg 490n work force distance 490n 5m 2450nm power work time 2450nm 20s 122 5nm s 122 5watt answer. A 12 5 w b 25 w c 60 w d 120 w e 210 w.

And doing it in 20 s. Lifting the person a distance of 5 m requires a work of 480 2 n 5 m 2401 j. Power work done time.

What power is needed to lift a 49 kg person a vertical distance of 5 0 m in 20 0 s. What power is needed to lift a 49 kg person a vertical distance of 5 0 m in 20 0 s. The combined mass of the platform and the crate is 207 kg.

We have the following data. The answer is roughly. What power is needed to lift a 49 kg person a vertical distance of 5 0 m in 20 0 s.

Work force x distance. G 10 or 9 81 whatever you are. A 12 5 w b 25 w c 60 w d 120 w e 210 w 22.

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